Question

I want to create water out of 45.4 Liters of Oxygen at STP. How much water will I produce?

STP: Standard Temperature and Pressure
72g H2O
36g H20
9g H20
18g H20

Answer 1

72.96 of water produce by 45.4 L of oxygen at STP.

Step-by-step explanation:

`H_2+(1)/(2)O_2\rightarrow H_2O`

1 mole of oxygen=22.4 L at STP

`(1)/(2)`\mole of oxygen=22.4/2=11.2 L

11.2 L of oxygen required to produce water=1 mole

1 L of oxygen required to produce water=1/11.2 mole

45.4 L of oxygen required to produce water=
`(1)/(11.2)* 45.4`

45.4 L of oxygen required to produce water=
`(45.4)/(11.2)`moles

1 mole of water=18 g

`(45.4)/(11.2)`moles of water=
`18* (45.4)/(11.2)`

`(45.4)/(11.2)`moles of water=72.96 g

Hence, 72.96 of water produce by 45.4 L of oxygen at STP.