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On a coordinate plane, rhombus W X Y Z is shown. Point W is at (7, 2), point X is at (5, negative 1), point Y is at (3, 2), and point Z is at (5, 5).

What is the perimeter of rhombus WXYZ?

StartRoot 13 EndRoot units
12 units
StartRoot 13 EndRoot units
20 units

User RoadieRich
by
4.9k points

2 Answers

2 votes

Answer:

C on edge 2021

Explanation:

I took the cumulative exam

User ZoFreX
by
4.5k points
3 votes

Answer:


P = 4√(13)

Explanation:

Given


W = (7, 2)


X = (5, -1)


Y = (3, 2)


Z =(5, 5)

Required

The perimeter

To do this, we first calculate the side lengths using distance formula


d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2

So, we have:


WX = \sqrt{(5- 7)^2 + (-1 - 2)^2


WX = √(13)


XY = √((3-5)^2 + (2--1)^2)


XY = √(13)


YZ = √((5-3)^2 + (5-2)^2)


YZ = √(13)


ZW = √((7 - 5)^2 + (2 - 5)^2)


ZW = √(13)

The perimeter is:


P = WX + XY + YZ + ZW


P = √(13)+√(13)+√(13)+√(13)


P = 4√(13)

User GMK
by
4.9k points