Question

Part C – RC Circuits in AC Mode 1. Derive Equation 5-6 from Equation 5-5. 2. Using the τ’s you calculated and your measured resistance: a. Calculate the capacitances of the capacitors. b. Compare your calculated and measured values via percent error.

Answer 1

Answer: hi your question is incomplete attached below is the complete question

1) attached below

2) a) 31 Ω, 302.9 Ω

b) 17.3 Ω , 26.4 Ω

Step-by-step explanation:

1) Deriving Eqn 5-6 from Eqn 5-5

attached below

2) using τ’s calculated and measured resistance

use given data

Tm1 = Rm1 * Cm1

= 329.3 * 333 * 10^-9 = 109.65 μs

Tm2 = Rm2 * Cm2

= 329.3 * 200 * 10^-9 = 658.6 μs

a) Capacitance of capacitors

For Cm1

t₁₂ = 72 μs = R₁' Cm1 log²

∴ R₁' = ( 72 * 10^-6 ) / ( 333 * 10^-9 log² )

= 31 Ω

For Cm2

t₁₂ = 40 μs , ∴ R₂' = 302.9 Ω

b) comparing calculated and measured values via percent error

errors

Rm1 - R₁' = 17.3 Ω

Rm2 - R₂' = 26.4 Ω