9514 1404 393
Answer:
maybe
Explanation:
It can be. It depends on the problem.
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The rules of exponents are ...
(a^b)/(a^c) = a^(b-c)
a^-b = 1/a^b
Clearly, for division problems if the denominator exponent is larger, the difference 'b-c' will be negative.
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You recall that an exponent is the way we show repeated multiplication.
x·x·x = x³
In division, like factors cancel, so ...

Now, consider the same problem "upside down."
