Answer:
2.39x10⁻⁴ moles
Step-by-step explanation:
As the problem asks us the number of moles of KIO₃ that were titrated, all that is required of us is to calculate how many moles of KIO₃ are there in 23.92 mL of a 0.0100 M solution (All moles in the samples are titrated).
We can do so by using the definition of molarity:
- Molarity = moles / liters
converting 23.92 mL ⇒ 23.92 / 1000 = 0.02392 L
- moles = 0.0100 M * 0.02392 L