Question

Please help it's for a test.

A car of mass 1000kg is traveling 30m/s

a) What is the kinetic energy?

b) How high will it have to travel up a hill to have the same potential as kinetic energy as this speed? Remember Ep-Ek

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Answer 1

Step-by-step explanation:

`KE=(1)/(2)mv^2` so filling in:

`KE=(1)/(2)(1000)(30)^2` so to 2 sig figs (which is actually not accurate, but oh well...)

KE = 450000 J

If we want to find out how high it will have to travel up a hill so that its PE is the same as the KE at this speed, we set the value for KE = to PE:

450000 = (1000)(9.8)h so

`h=(450000)/((1000)(9.8))=45.9m`