Question

Plz help fast thank you

Answer 1

tanA =
`(4)/(3)`

Explanation:

Using the identity

tanA =
`(sinA)/(cosA)` =
`((4)/(7) )/((3)/(7) )` =
`(4)/(7)` ×
`(7)/(3)` =
`(4)/(3)`

Answer 2

`\tan(a) = ( \sin(a) )/( \cos(a) )`

`\tan(a) = ( (4)/(7) )/( (3)/(7) )`

`\tan(a) = (4)/(3)`