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Center of triangles geometry acellus pls help

Center of triangles geometry acellus pls help-example-1

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Answer:

Explanation:

All the vertices of triangle are equal distant from circum center.

RC = PC = QC

RC = PC

5x - 15 = 3x + 7

Add 15 to both sides

5x = 3x + 7 + 15

5x = 3x + 22

Subtract 2x from both sides

5x- 3x = 22

2x = 22

Divide both sides by 2

x = 22/2

x = 11

QC = 51 - x

= 51 - 11

QC = 40

User Robert Davis
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