Answer:
![P(Atleast\ 1) = 0.9999992](https://img.qammunity.org/2022/formulas/mathematics/high-school/rncqu39fhs8g8elpkvjlbsrzl12q2avcn7.png)
Explanation:
Given
--- rate of hard disk drives failure
--- number of hard disk drives
See comment for complete question
Required
![P(Atleast\ 1)](https://img.qammunity.org/2022/formulas/mathematics/high-school/km5xxyd6lfwsap6ibcltvurmfauju8ow69.png)
First, calculate the probability that the none of the 4 selected is working;
![P(none) = p^4](https://img.qammunity.org/2022/formulas/mathematics/high-school/e31l0pe12ts61v7xu0g5jz36z003tgn3dg.png)
![P(none) = (3\%)^4](https://img.qammunity.org/2022/formulas/mathematics/high-school/s4dh75g6colq21ze8n3wlxzj8j41tims97.png)
![P(none) = (0.03)^4](https://img.qammunity.org/2022/formulas/mathematics/high-school/wn7rbhuqpyifobvxl0vrt86myvldd1cqmc.png)
Using the complement rule, the probability that at least 1 is working is:
![P(Atleast\ 1) = 1 - P(none)](https://img.qammunity.org/2022/formulas/mathematics/high-school/eox9rfztfe8a8nqxhklq2yut9pg95oglkh.png)
This gives:
![P(Atleast\ 1) = 1 - 0.03^4](https://img.qammunity.org/2022/formulas/mathematics/high-school/qi1c32ydhsyifpu5mdap139zdtl2vh8mc6.png)
![P(Atleast\ 1) = 0.9999992](https://img.qammunity.org/2022/formulas/mathematics/high-school/rncqu39fhs8g8elpkvjlbsrzl12q2avcn7.png)