Answer:
The minimum value of f(x) is greater than the minimum value of g(x).
Explanation:
Given
--- vertex of f(x)
--- g(x) equation
Required
Which of the options is true
First, we identify the vertex of g(x)
A quadratic function is represented as:

Where:
vertex
So, we have:


If
, then the curve opens upward
From the question, we understand that f(x) also open upward. This means that both functions have a minimum
The minimum is the y (or k) coordinate
So, we have:
--- vertex of f(x)
--- vertex of g(x)
The minimum of both are:
---- f(x)
---- g(x)
By comparison:

Hence, f(x) has a greater minimum