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A softball pitcher throws a softball to a catcher behind home plate. The softball is 3 feet above the ground when it leaves the pitcher's hand at a velocity of 50 feet per second. If the softball's acceleration is –16 ft/s2, which quadratic equation models the situation correctly?

User Godinall
by
4.2k points

2 Answers

2 votes

Answer:

b on edge

Explanation:

User Kadir Erdem Demir
by
3.8k points
3 votes

Answer:

The function is:


f(t) = -16t^2 + 50t + 3

Explanation:

Given


height = 3ft


velocity = 50ft/s


acceleration = -16ft/s^2

Required

The function

Let t represents time;

So, we have:


f(t) = acceleration * t^2 + velocity * t + height

So, we have:


f(t) = -16* t^2 + 50* t + 3


f(t) = -16t^2 + 50t + 3