Question

Mathematics puzzle from my calculus text book.

Answer 1

`{ \tt{g(x) = a {x}^(2) + bx + c = 0 }} \\ { \tt{f(x) = {a'x}^(2) + b 'x + c' = 0}} \\ { \boxed{ \bf{f(g(x)) = g(f(x))}}} : \\ { \tt{ =( (a)/(a'))x {}^(2) + ( (b)/(b')) x} + (c)/(c') } = 0`