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3 votes
A body initially at rest travels a distance 100 m in 5 s with a constant acceleration. calculate

(i) Acceleration

(ii) Final velocity at the end of 5 s.​

User MikeH
by
5.2k points

2 Answers

4 votes

Answer:

(i)8m/s²(ii)40m/s

Step-by-step explanation:

according to the formula

½at²=s.

then substituting the data

½a•5²=100

a=8m/s²

v=at=8•5=40m/s

User Asheyla
by
5.1k points
5 votes

Answer:

(I)


{ \bf{s = ut + (1)/(2) a {t}^(2) }} \\ 100 = (0 * 5) + (1)/(2) * a * {5}^(2) \\ 200 = 25a \\ { \tt{acceleration = 8 \: m {s}^( -2) }}

(ii)


{ \bf{v = u + at}} \\ v = 0 + (8 * 5) \\ { \tt{final \: velocity = 40 \: m {s}^( - 1) }}

User Erik Pragt
by
5.0k points