Answer:
The difference in the H⁺ concentration between the two solutions is approximately equal to the H⁺ concentration of the acidic solution.
Explanation:
The pH is given by:
![pH = -log[H^(+)]](https://img.qammunity.org/2022/formulas/mathematics/college/7tutr55kpdbppotgdyfoibj24lbfgn3c2e.png)
Where:
: is the concentration of hydrogen ions.
For the basic solution (pH = 11.2), the concentration of H⁺ is given by:
![[H^(+)]_(b) = 10^(-pH) = 10^(-11.2) = 6.31 \cdot 10^(-12)](https://img.qammunity.org/2022/formulas/mathematics/college/902ohf3qpuisihvd2wbvkq8jdh0kltopgm.png)
And, for the acidic solution (pH = 2.4) we have:
![[H^(+)]_(a) = 10^(-pH) = 10^(-2.4) = 3.98 \cdot 10^(-3)](https://img.qammunity.org/2022/formulas/mathematics/college/nd8snanxfner4sey3ubmcq0eu05e5hj9wr.png)
Hence, the difference in the concentration of H⁺ between the two solutions is:
![\Delta H^(+) = [H^(+)]_(a) - [H^(+)]_(b) = 3.98 \cdot 10^(-3) - 6.31\cdot 10^(-12) = 3.98 \cdot 10^(-3)](https://img.qammunity.org/2022/formulas/mathematics/college/tcfrehl9b3k2pvq2790y7f3t4ctxekjsm2.png)
Therefore, the difference in the H⁺ concentration between the two solutions is approximately equal to the H⁺ concentration of the acidic solution.
I hope it helps you!