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The angle of elevation of the top of the tower from a point on the ground is 30 degree, If the height of the tower is 40 space m e t e r s, then the distance between the tower and the point is​

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7 votes

Answer:


40\sqrt3\ m

Explanation:

Given that,

The height of the tower, h = 40 m

The angle of elevation is 30°

We need to find the distance between the tower and the point. Let the distance is x. Using trigonometry,


\tan(30)=(h)/(x)\\\\(1)/(\sqrt3)=(40)/(x)\\\\x=40\sqrt3\ m

So, the distance between the tower and the point is equal to
40\sqrt3\ m.

User Randin
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