Question

2. A Cylindrical hot water tank is closed at both ends. The radius of the tank is 0.5m and the height is 0.75.calculate i. The volume of the Cylinder it. The total surface area of the tank (take π =22 out of 7​

Answer 1

1. Formula for volume of a cylinder;

V = πr^2h

where pi is 3.14 or 22/7, r is the radius(0.5) which is squared, and h is the height

plug in the actual values;

V = πr^2h

V = 3.14 * 0.5^2 * 0.75

V = 3.14 * 0.25 * 0.75

V = 0.785 x 0.75

V = 0.58875^3 meters or 0.59^3 meters, is the volume. (round to whatever place they covet)

2. Formula for surface area of a cylinder;

SA = 2πr(r + h)

Plug in the actual values:

SA = 2πr(r + h)

SA = 2 x 3.14 x 0.5(0.5 + 0.75)

SA = 2 x 3.14 x 0.5(1.25)

SA = 2 x 3.14 x 0.625

SA = 3.925 meters or 3.93 meters is the surface area.

Answer 2

Volume = 0.59 m³

Surface Area = 3.93 m²

Explanation:

Given :-

- Radius = 0.5 cm

- Height = 0.75 cm

To Find :-

- Volume

- Surface Area

Solving :-

Volume = πr²h

= 22/7 x (0.5)² x 0.75

= 22/7 x 1/4 x 3/4

= 66/112

= 33/56 m³

= 0.59 m³

Surface Area = 2πr (r + h)

= 2 x 22/7 x 0.5 (0.5 + 0.75)

= 22/7 x 5/4

= 110/28

= 55/14 m²

= 3.93 m²

Solution :-

Volume = 0.59 m³

Surface Area = 3.93 m²