Question

Find the value of x,if the distance between p(5,2) and Q(x,-2)be 5 units.​

Answer 1

points srru

Explanation:

Answer 2

Explanation:

PQ=√((x-5)²+(-2-2)²)=√((x-5)²+16)=5

squaring

(x-5)²+16=25

(x-5)²=25-16=9

x-5=±3

x=-3+5,3+5

or x=2,8