Question

Un proton penetra perpendiculares en un campo magnetico de 5 teslas con una velocidad de 2.10 m/s calcula

Answer 1

The magnetic force acting on the proton is 1.68 x 10^-18 N.

Step-by-step explanation:

magnetic field, B = 5 T

speed , v = 2.1 m/s

charge q = 1.6 x 10^-19 C

Angle, A = 90 degree

The magnetic force on the charge particle is given by

`F = q v B sin A\\\\F = 1.6* 10^(-19)* 2.1* 5* sin 90\\\\F = 1.68* 10^(-18) N`