Question

A ball is thrown upward with an initial velocity (v) of 15 meters per second. Suppose that the initial height (h) above the ground is 7

meters. At what time will the ball hit the ground? The ball is on the ground when S = 0. Use the equation S = -52 + vt + h.
The ball will hit the ground in how many
seconds?

Answer 1

Explanation:

Your equation is weird. The position equation for this situation is

`s(t)=-4.9t^2+15t+7` and set it equal to 0 to solve for the time it takes to hit the ground. Those times come out to be

t = 3.47 sec and t = -.411 sec. But since time can never be negative, our time is 3.47 seconds

(What is that -52?)