Question

NEED LINEAR ALGEBRA ANSWER ASAP
B IS INCORRECT

Answer 1

4th option

Explanation:

3
`\left[\begin{array}{ccc}2\\-1\\\end{array}\right]` -
`\left[\begin{array}{ccc}0\\-1.5\\\end{array}\right]` ← multiply the components of the first matrix by 3

=
`\left[\begin{array}{ccc}6\\-3\\\end{array}\right]` -
`\left[\begin{array}{ccc}0\\-1.5\\\end{array}\right]` ← subtract corresponding components

=
`\left[\begin{array}{ccc}6-0\\-3-(-1.5)\\\end{array}\right]`

=
`\left[\begin{array}{ccc}6\\-3+1.5\\\end{array}\right]`

=
`\left[\begin{array}{ccc}6\\-1.5\\\end{array}\right]`

Answer 2

Choice D

Explanation:

Multiply the scalar into the matrix

3*2

3*-1

The first matrix becomes

6

-3

6 - 0

-3 =1.5

We are subtracting a negative so it is like adding

6 + 0

-3 + 1.5

6

-1.5

Choice D