A boat takes off from the dock at 2.5m/s and speeds up at 4.2m/s2 for 6.0 seconds how far has the boat traveled

asked Jul 21, 2022 105k views

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5 votes

Answer:

The answer is "91 m"

Step-by-step explanation:

$v_0 = 2.5 \ (m)/(s)\\\\a = 4.2\ (m)/(s^2)\\\\t = 6.0\ s\\\\\Delta x=?$

Using formula:

$\Delta x = v_0 t +(1)/(2) at^2\\\\$

$= 2.5 * 6.0 +(1)/(2) * 4.2 * 6.0^2\\\\= 90.6\ m \approx 91\ m$

Lfkwtz answered Jul 27, 2022

4.0k points

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