Question

A boat takes off from the dock at 2.5m/s and speeds up at 4.2m/s2 for 6.0 seconds how far has the boat traveled

Answer 1

The answer is "91 m"

Step-by-step explanation:

`v_0 = 2.5 \ (m)/(s)\\\\a = 4.2\ (m)/(s^2)\\\\t = 6.0\ s\\\\\Delta x=?`

Using formula:

`\Delta x = v_0 t +(1)/(2) at^2\\\\`

`= 2.5 * 6.0 +(1)/(2) * 4.2 * 6.0^2\\\\= 90.6\ m \approx 91\ m`