Question

Calculate surface tension of an enlarged radius of 4cm to 6cm and amount of work necessary for enlargement was 1.5×10^-4 joules

Answer 1

`T=7.5*10^(-5)`

Step-by-step explanation:

From the question we are told that:

Radius
`r=2cm`

Work done
`W=1.5×10^-4 joules`

Generally the equation for Work done is mathematically given by

`W=T.dA`

Therefore

`T=(W)/(dr)`

`T=(1.5*10^(-4))/(2)`

`T=7.5*10^(-5)`