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An open 1-m-diameter tank contains water at a depth of 0.5 m when at rest. As the tank is rotated about its vertical axis the center of the fluid surface is depressed. At what angular velocity will the bottom of the tank first be exposed

1 Answer

6 votes

Answer:

Angular velocity (w) = 8.86 rad/s

Step-by-step explanation:

Angular velocity (w) =
\sqrt{} 4ghi/R^(2)

g= 9.81 m/s

R= 0.5

hi (initial depth) = 0.5m

Hence=
\sqrt4* 9.81* 0.5/0.5^(2) = 8.86 rad/s

User Simon Tesar
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