Question

At what frequency would an inductor of inductance 0.8H have a reactance of 12000^?​

Answer 1

Step-by-step explanation:

The inductive reactance
`X_L` is given by

`X_L = \omega L = 2 \pi fL`

Solving for f, we get

`f = (X_L)/(2 \pi L) = \frac{12000\:\text{ ohms}}{2\pi (0.8\:H)}`

`\:\:\:\:\:\:\:= 2387.3\:\text{Hz}`