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Hydrochloric acid is widely used as a laboratory reagent in refining ore for the production of tin and tantalum, and as a catalyst in organic reactions. Calculate the number of moles of HCl in 62.85 mL of 0.453 M hydrochloric acid.

User Mkjh
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1 Answer

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Answer: 0.0285 moles of HCl is present in given amount of solution.

Step-by-step explanation:

Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:


\text{Molarity of solution}=\frac{\text{Moles of solute}* 1000}{\text{Volume of solution (mL)}} .....(1)

Given values:

Molarity of HCl = 0.453 M

Volume of solution = 62.85 mL

Putting values in equation 1, we get:


0.453mol/L=\frac{\text{Moles of HCl}* 1000}{62.85}\\\\\text{Moles of HCl}=(0.453* 62.85)/(1000)=0.0285moles

Hence, 0.0285 moles of HCl is present in given amount of solution.

User Bentolor
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