Answer:
Increasing interval is:
![(-\infty, 0)](https://img.qammunity.org/2022/formulas/mathematics/high-school/reopauxrhs5sqlnjc4b3puu506jerypl28.png)
Decreasing interval is:
![(0, \infty)](https://img.qammunity.org/2022/formulas/mathematics/high-school/9beck1bqcvq8cuic2dsvpx2e8we0pmagdl.png)
Constant at no interval
Explanation:
Given
See attachment for graph
Solving (a): The domain
From, the attached graph, we have:
![y = -x^2 + 4](https://img.qammunity.org/2022/formulas/mathematics/high-school/ls5ayiaxmg4685yiegsa57bzrry9vqgizi.png)
The degree of the polynomial (i.e 2) is even.
Hence, the domain is the set of all real numbers, i.e.
![Domain = (-\infty, \infty)](https://img.qammunity.org/2022/formulas/mathematics/high-school/zs3gj74nedr80lyubek7ktcvdbqf84ocs9.png)
Solving (b): The range
The curve of
opens downward, and the maximum is:
![y_(max) = 4](https://img.qammunity.org/2022/formulas/mathematics/high-school/847gypt7nnt6l2mmtx7fd50ed4nth0vkzk.png)
This means that the minimum is:
![y_(mi n) = -\infty](https://img.qammunity.org/2022/formulas/mathematics/high-school/4hxto7oqev6ime0udcpphzrile10iy18n1.png)
Hence, the range of the set is:
![Range = (-\infty, 4]](https://img.qammunity.org/2022/formulas/mathematics/high-school/s4a5rf3c8x3p6h0w5k6uw7qhdu054jjgcf.png)
Solving (c): Interval where the function increases/decreases/constant
In (a), we have:
![Domain = (-\infty, \infty)](https://img.qammunity.org/2022/formulas/mathematics/high-school/zs3gj74nedr80lyubek7ktcvdbqf84ocs9.png)
Split to 2 (at vertex x = 0)
and
![(0, \infty)](https://img.qammunity.org/2022/formulas/mathematics/high-school/9beck1bqcvq8cuic2dsvpx2e8we0pmagdl.png)
So:
The increasing interval is:
![(-\infty, 0)](https://img.qammunity.org/2022/formulas/mathematics/high-school/reopauxrhs5sqlnjc4b3puu506jerypl28.png)
The decreasing interval is:
![(0, \infty)](https://img.qammunity.org/2022/formulas/mathematics/high-school/9beck1bqcvq8cuic2dsvpx2e8we0pmagdl.png)
The function has a tangent at
but at no interval, was the function constant