Just need help here pls

asked Mar 16, 2023 166k views

24 votes

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12 votes

Answer:

k=6, k=-1

Explanation:

(k+3)/(3)-(2)/(k-5)=1

$\implies ((k+3)(k-5))/(3(k-5))-(3 \cdot 2)/(3(k-5))=1$

$\implies (k^2-2k-15-6)/(3(k-5))=1$

$\implies k^2-2k-21=3k-15$

$\implies k^2-5k-6=0$

$\implies (k-6)(k+1)=0$

$\implies k=6, k=-1$

Raultm answered Mar 19, 2023

5.7k points

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