Question

What is the strength of the magnetic field a distance 4.4 mm above the center of a circular loop of radius 0.8 mm and current 474.1 A

Answer 1

B = 0.118 T

Step-by-step explanation:

From Biot-Savart Law:

`B = (\mu_o I)/(2\pi r)`

where,

B = strength of magnetic field = ?

μ₀ = 4π x 10⁻⁷ Tm/A

I = current enclosed = 474.1 A

r = radius = 0.8 mm = 8 x 10⁻⁴ m

Therefore,

`B = ((4\pi\ x\ 10^(-7)\ Tm/A)(474.1\ A))/(2\pi(8\ x\ 10^(-4)\ m))`

B = 0.118 T