Question

Does anyone know how to solve these?

Answer 1

1st graph: slope is -1 and equation is y=-x+5

2nd graph: slope is 2/5 and equation is y=2/5x-3

Explanation:

y=mx+b is slope-intercept form.

It's call that because this forn tells us the slope,m, and the y-intercept,b.

The first graph you have identified b as 5 since you said the y-intercept was (0,5).

Now we just find slope by finding rise/run.

(0,5) is marked and we see another point has been marked, I will start at (0,5) go down 2 and right 2. This means rise=-2 and run=2 which means the slope=-2/2 and that reduces to -1.

The equation for first graph is y=-1x+5 or y=-x+5.

So again you have no problem identifying the y-intercept which is b=-3.

Now just count the rise/run to the other point. Starting at y-intercept we have to go up 2 and right 5 to get to the other point so m=2/5.

Answer 2

remember the slope= rise/run. so for the first graph, there are coordinates (0,5) and (2,3). so the rise = 3-5=-2 and the run=2-0=2 so the slope=-2/2=-1. and since the equation for a line is y=mx+ b, where m is the slope and b is the y intercept, the answer is y=-x+5

then just do the same process with the other question to get y=(2/5)x-3