Answer:
(2x^2 + x-3)/(4x^2-9)
Explanation:
The denominator looks like an expression in which we have applied the difference of two squares to
In that case, we know that;
a^2-b^2 = (a-b)(a+ b)
That means we would be have 2x + 3 as the other denominator factor and the expression at the denominator would be;
(2x + 3)(2x-3) = 4x^2 - 9
Also, we would have to cancel out 2x + 3 from the numerator too, so as to be left with only the binomial
That means;
(2x+3)(x-1) = 2x^2-2x+ 3x - 3 = 2x^2+x -3
So we have the original expression as;
(2x^2 + x-3)/(4x^2-9)