Question

If you produce 35.7 grams of sodium chloride how many molecules of Chlorine gas were

needed?
2Na + Cl2 --> 2NaCl
(PLS HELP)

Answer 1

Answer:
`7.36* 10^(23)` number of molecules of chlorine gas are needed.

Step-by-step explanation:

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

`\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}` ......(1)

Given mass of sodium chloride = 35.7 g

Molar mass of sodium chloride = 58.44 g/mol

Plugging values in equation 1:

`\text{Moles of sodium chloride}=(35.7g)/(58.44g/mol)=0.611 mol`

The given chemical equation follows:

`2Na+Cl_2\rightarrow 2NaCl`

By the stoichiometry of the reaction:

If 1 mole of sodium chloride is produced from 2 moles of chlorine gas

So, 0.611 moles of sodium chloride will be produced from =
`(2)/(1)* 0.611=1.222mol` of chlorine gas

According to the mole concept:

1 mole of a compound contains
`6.022* 10^(23)` number of molecules

So, 1.222 moles of chlorine gas will contain =
`(6.022* 10^(23))/(1mol)* 1.222mol=7.36* 10^(23)` number of molecules

Hence,
`7.36* 10^(23)` number of molecules of chlorine gas is needed.