A (x) = x ^ 4-2022x ^ 3-2022x ^ 2-2022x-2022 A (2023)?

Jpgooner asked Sep 12, 2023

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A (x) = x ^ 4-2022x ^ 3-2022x ^ 2-2022x-2022
A (2023)?

Jpgooner asked Sep 12, 2023

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11 votes

Answer:

Explanation:

Through simply substituting your value into everywhere there is an 'x', you can get your answer.

$A(2023)=(2023)^4-2022(2023)^3-2022(2023)^2-2022(2023)-2022\\A(2023)=1$

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