8.8k views
1 vote
Help please i need it bad

Help please i need it bad-example-1

1 Answer

6 votes

Answer:

-13, -3

15, 2.6

Explanation:

x, y are the numbers

x = 5y + 2

x×y = 39

(5y + 2)×y = 39

5y² + 2y - 39 = 0

the solution of a quadratic equation :

y = (-b ± sqrt(b² - 4ac))/2a

a = 5

b = 2

c = -39

y = (-2 ± sqrt(2² - 4×5×-39))/2×5 =

= (-2 ± sqrt(4 + 780))/10 =

= (-2 ± sqrt(784))/10 = (-2 ± 28)/10

y1 = (-2 + 28)/10 = 26/10 = 2.6

y2 = (-2 - 28)/10 = -30/10 = -3

x1 = 5×2.6 + 2 = 13 + 2 = 15

x2 = 5×-3 + 2 = -15 + 2 = -13

User Seena V P
by
3.3k points