Question

What is an
equation of the line that passes through the points (0,6) and (-3,2)?

Answer 1

y = 4/3 x + 6

Explanation:

M = -4/-3 = 2/3

y = 4/3 X + B

6 = 4/3(0) + B

B=6

Answer 2

Explanation:

y=mx+b is the general equation of a line, where

m= slope = (y2-y1)/(x2-x1)= (6-2)/(0- -3)= 4/3

b= y intercept

for point (0,6)

y=(4/3)x+b will become 6=(4/3)*0 +b, so b=6

the equation of the line that passes trough the given points is

y= (4/3) x +6