Question

Please help it would be much appreciated!!

There are 4 routes from Danbury to Hartford and 6 routes from Hartford to Springfield. You need to drive from Danbury to Springfield for an important meeting. You don’t know it, but there are traffic jams on 2 of the 4 routes and on 3 of the 6 routes. Answer the following:

a. You will miss your meeting if you hit a traffic jam on both sections of the journey. What is the probability of this happening?
b. You will be late for your meeting if you hit a traffic jam on at least one, but not both sections of the trip. What is the probability of this?
c. What is the probability that you will hit no traffic jam?

Answer 1

a) P) 0.25 = 1/4 both

b) P) 0.75 = 3/4 one

c) P) 0.25 = 1/4 none

Explanation:

4 routes to D + H

6 routes to H + S

= D H S

4 | 6

- 2 | -3

= 2 | 3 = route 1 = 2/4 and route 2 = 3/6

= 1/2 route 1 and 1/2 route 2

Answer a ) = 1/2 x 1/2 = 0.25 = 1/4 = 0.25 probability

Answer b) = 1- (1/2 x 1/2) = 1- 0.25 = 3/4 = 0.75 probability

Answer c) = 1/2 x 1/2 = 0.25 = 1/4 = 0.25 probability