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There are two known issues with a certain model of new car. The first issue, A, occurs with a probability of P(A)=0.1. B is another known issue with the car. If it is known that either event occurs with a probability of P(A OR B)=0.93, and that both events occur with a probability of P(A AND B)=0.07, calculate P(B).

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Answer:


P(B) = 0.90

Explanation:

Given


P(A) = 0.1


P(A\ or\ B) = 0.93


P(A\ and\ B) = 0.07

Required


P(B)

To do this, we make use of:


P(A\ or\ B) + P(A\ and\ B) = P(A) + P(B)

Make P(B) the subject


P(B) = P(A\ or\ B) + P(A\ and\ B) - P(A)

So, we have:


P(B) = 0.93 + 0.07 - 0.1


P(B) = 0.90

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