Question

Solve the equation to find where the treste ground levelEnter your answers from least to greatest and round to the nearest The meets the ground at and

Answer 1

The trestle meets ground level at 0.875 units and 9.125 units

Explanation:

Poorly formatted question.

The given equation is:

`y = -x^2 + 10x - 8`

Required

The point where the trestle gets to the ground level

To do this, we set
`y = 0`

So, we have:

`-x^2 + 10x - 8 = 0`

Multiply through by -1

`x^2 -10x + 8 = 0`

Solve using quadratic formula:

`x= (-b \± √(b^2 - 4ac))/(2a)`

Where:

`a = 1; b =-10; c = 8`

So, we have:

`x= (-(-10) \± √((-10)^2 - 4*1*8))/(2*1)`

`x= (-(-10) \± √(68))/(2*1)`

`x= (-(-10) \± 8.25)/(2)`

`x= (10 \± 8.25)/(2)`

Solve the fraction

`x= 5 \± 4.125`

Split

`x= 5 + 4.125\ or\ x= 5 - 4.125`

`x= 9.125\ or\ x= 0.875`