Answer:
a. 2
Explanation:
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean
and standard deviation
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
and standard deviation
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean
and standard deviation
![s = \sqrt{(p(1-p))/(n)}](https://img.qammunity.org/2022/formulas/mathematics/college/21siyq2l0d9z8pcii2ysmig6q1uk55fvwj.png)
Standard deviation is known to be 14.
This means that
![\sigma = 14](https://img.qammunity.org/2022/formulas/mathematics/college/3wl8vgru5ugoviddjtl5k92u31x5nbqgm0.png)
Sample of 49
This means that
![n = 49](https://img.qammunity.org/2022/formulas/mathematics/college/32rokp6sqhztos15hxinfnnwbrb02wikjg.png)
The standard error of the mean is
![s = (\sigma)/(√(n)) = (14)/(√(49)) = (14)/(7) = 2](https://img.qammunity.org/2022/formulas/mathematics/college/mud9k05lo25c040jazvclccepx5sp6jwrc.png)
So the correct answer is given by option a.