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A drone flying horizontally at a height of 25 m approaches a point above a person. If the mass of the drone is 11 kg, and its speed is 9.5 m/s, what is the angular momentum of the drone with respect to the person when the it is at a horizontal distance 125 m away.

1 Answer

5 votes

Answer:

L = 2.61 10³ kg m² / s

Step-by-step explanation:

Let's approximate the drone to a particle the angular momentum is

L = r x p

L = m r v sin θ

in this case v = 9.5 m / s the mass of the drone is m = 11 kg.

The distance can therefore be found using the Pythagorean theorem, but we can see that the relation

r_perpendicular = r sin θ

r_perpendicular = 25 m

as the flight is horizontal this height does not change

L = m v r_perpendicular

let's calculate

L = 11 9.5 25

L = 2.61 10³ kg m² / s

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