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How many different committees can be formed from 12 teachers and 43 students if the committee consists of 3 teachers and 4 ​students?

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User Notaras
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1 Answer

6 votes

Answer:

  • 27150200

Explanation:

Combination of 3 teachers out of 12:

  • 12C3 = 12!/9!3! = 10*11*12/2*3 = 220

Combination of 4 students out of 43:

  • 43C4 = 43!/39!4! = 40*41*42*43/2*3*4 = 123410

Total combinations:

  • 220*123410 = 27150200
User LONGI
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