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Click Stop Using the slider set the following: coeff of restitution to 1.00 A velocity (m/s) to 6.0 A mass (kg) to 6.0 B velocity (m/s) to 0.0 Calculate what range can the mass of B be to cause mass A to bounce off after the collision. Calculate what range can the mass of B be to cause mass A to continue forward after the collision. Check your calculations with the simulation. What are the ranges of B mass (kg)

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Answer:


M_b=6kg

Step-by-step explanation:

From the question we are told that:

Coefficient of restitution
\mu=1.00

Mass A
M_a=6kg

Initial Velocity of A
U_a=6m/s

Initial Velocity of B
U_b=0m/s

Generally the equation for Coefficient of restitution is mathematically given by


\mu=(V_b-V_a)/(U_a-U_b)


1=(v_B)/(6)


V_b=6*1


V_b=6m/s

Generally the equation for conservation of linear momentum is mathematically given by


M_aU_a+M_bU_b=M_aV_a+M_bV_b


6*6+=M_b*6


M_b=6kg

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