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Find the zeros of the function g(x) = 3x^2 + 42
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Find the zeros of the function g(x) = 3x^2 + 42

User Shu Suzuki
by
7.6k points

1 Answer

5 votes

Answer:

There are no zeroes.

Explanation:

If you look at the y intercept. It is 42. Furthermore, since there is an asymptote under that, the function is always increasing. Thus, there are no zeroes.

User Collin Chaffin
by
6.8k points
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