Question

A 0.495-kg hockey puck, moving east with a speed of 4.50 m/s , has a head-on collision with a 0.720-kg puck initially at rest. Assuming a perfectly elastic collision, what will be the speed (magnitude of the velocity) of each object after the collision?

Answer 1

a)
`v_1=-0.833m/s`

b)
`V_2=12.5m/s`

Step-by-step explanation:

From the question we are told that:

Hockey puck Mass
`m_1=0.495kg`

Hockey puck Speed
`u_1=4.50m/s`

Puck Mass
`m_2=0.720kg`

Assuming

Initial speed of Puck
`u_2=0`

Generally the equation for Speed of First Puck is mathematically given by

`v_1=((m_1-m_2)/(m_1+m_2))*v_1+((2m_2)/(m_1+m_2))u_2`

`v_1=((0.495-0.720)/(0.495+0.720))*4.50+0`

`v_1=-0.833m/s`

Generally the equation for Speed of Second Puck is mathematically given by

`V_2=((2m_1)/(m_1+m_2))u_2-((m_1-m_2)/(m_1+m_2))v`

`V_2=((2*0.495)/(0.495*0.720))*4.50-0`

`V_2=12.5m/s`