Question

How many grams of lithium chloride are in a 3.0 Molarity solution of 0.5 L?

Answer 1

63.52g of LiCl are in a 3.0 molarity solution of 0.5L

Step-by-step explanation:

Moles = Molarity x Volume

Molarity = 3.0 mol/L

Volume = 0.5L

Moles = (3.0) x (0.5)

Moles = 1.5

In order to find the grams dissolved in the solution, we must first find the molar mass of Lithium Chloride (LiCl).

Molar mass of LiCl = (6.9) + (35.45) = 42.35g/mol

Now we multiply the moles by the molar mass of LiCl to get the grams of LiCL dissolved in the solution.

1.5 * 42.35 = 63.52g of LiCl

Answer 2

Step-by-step explanation:

LiCl2 3 M =

in sol. 1 L there is LiCl2 3 mol

if sol. 0.5 L there is LiCl2 0.5×3 = 1.5 mol

LiCl2 = 6.9 + 35.5(2)

= 6.9 + 71

= 77.9 g