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4 votes
The axis of symmetry for the graph of the function f(x) =

-x2 + bx + 10 is x=6. What is the value of b?
--3
Ο Ο Ο Ο

User Adekemi
by
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1 Answer

4 votes

Answer:

12

Explanation:


y = - x {}^(2) + bx + 10 \\ y = - (x {}^(2) - bx - 10) \\ y = -( (x - (b)/(2) ) {}^(2) - \frac{b {}^(2) }{4} - 10) \\ y = - (x - (b)/(2) ) {}^(2) + 10 + \frac{b {}^(2) }{4} \\ \\ therefore \: (b)/(2) = 6 \\ b = 12

User Grafbumsdi
by
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