Question

if escape velocity and orbital velocity of a satellite for Orbit close to the Earth's surface then these are related by​

Answer 1

The ratio of the escape velocity to the orbital velocity is
`\sqrt 2`.

Step-by-step explanation:

The minimum velocity given to an object so that it escapes from the earth's gravitational pull is called escape velocity.

The formula of the escape velocity is

`v=\sqrt(2GM)/(R)`

The velocity of an object in the orbit around the earth is called orbital velocity.

The formula of the orbital velocity is

`v=\sqrt(GM)/(R)`

The ratio of the escape velocity to the orbital velocity is

`(v_e)/(v_o)=\sqrt 2`