1 Answer

EdFred · Answer 1 · 2022-11-21T00:09:16+0000

Answer:

n = 0.21 moles

Step-by-step explanation:

Given that,

Volume, V = 0.84 L

Pressure, P = 4.6 atm

T = 222 K

We need to find the number of moles of Neon gas. We know that,

PV = nRT

Where

n is the number of moles

R i the gas constant, R = 0.08206 L-atm/mol-K

Put all the values,

$n=(PV)/(RT)\\\\n=(4.6* 0.84)/(0.08206 * 222)\\\\n=0.21\ \text{moles}$

So, there are 0.21 moles of Neon gas.

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