Answer: The change in momentum is +20 kg.m/s
Step-by-step explanation:
To calculate the final velocity of object, we use the first equation of motion:

where,
v = final velocity
u = initial velocity = 0 m/s
a = acceleration =

t = time = 0.5 s
Putting values in above equation, we get:

Momentum is defined as the product of the mass and velocity of an object. It is given by the equation:

where,
p = momentum
m = mass of object = 2 kg
Let the upward velocity be positive and the downward velocity be negative
When the object is dropped, the velocity is downward
v = -5m/s
Initial momentum =

When the object is bounced back, the velocity is upward
v = +5m/s
Final momentum =

Change in momentum = Final - Inital
Change in momentum = [10 - (-10)] = +20 kg.m/s
Hence, the change in momentum is +20 kg.m/s