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An experiment was performed under identical conditions as yours. The absorbance of the penny solution was recorded as 0.219 absorbance units. A calibration plot of absorbance vs. concentration of Cu(II) (M) yielded the following trendline equation:

y= 11.589x - 0.0002

Required:
What is the concentration (mol/L) of the penny solution?

1 Answer

6 votes

Answer:

Concentration C = 0.0189 mol/L

Step-by-step explanation:

From the given information:

Let consider the formula used in calculating the concentration according to Beer's law:


\mathtt{A =\varepsilon * L * C} --- (1)

here;

A = absorbance

ε = coefficient of molar absorptivity

L = path length

C = concentration (mol/L)

Also, from Beer law plot:

y = mx+b

where,

y represent absorbance A

b represents intercept

m represents the coefficient of molar absorptivity ε

and x represents the concentration(C).

replacing the substituted entities

A = ε × C + b ---- (2)

Making the concentration the subject of the above formula:


C = (A-b)/(\varepsilon)----(3)

From y = 11.589x - 0.0002

A = 11.589 *C - 0.0002

Given that:

A = 0.219

0.219 = 11.589 *C - 0.0002

0.219 + 0.0002 = 11.589 *C

C = 0.2192/11.589

C = 0.0189 mol/L

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