177k views
5 votes
Please help me!

The diagram shows the distance time graph of a bus in 45 minutes calculate

a) the period of time that the bus is stationery

b) the speed in km/h¯¹ in the first 5 minutes.

c) the value of s, if the speed is 80 km/h¯¹

d) describe the motion of bus in the last 20 minutes​

Please help me! The diagram shows the distance time graph of a bus in 45 minutes calculate-example-1
User Jtello
by
5.7k points

1 Answer

2 votes

Answer:

a) 20 minutes

b) 36 km/h

c) 33.67 km

d) continuous driving without any stationary phases.

Explanation:

by the way, speed is specified in distance per time unit. in your example as km/h. and that is how your write this.

not km/h¯¹. that would be wrong, as that would actually be km×h. but you can write e.g. km×h¯¹. that is the same as km/h.

between minutes 5 and 25 there is no progress in distance. so, for these 20 minutes the bus was stationary.

in the first 5 minutes the bus drove 7-4=3 km.

so, in 5 minutes 3 km. to determine the speed we need to calculate up to see, how many km would be have driven in a full hour (60 minutes). the same factor for the time has then to be applied also to the distance to keep the ratio unchanged.

5 × x = 60

x = 12

3 × 12 = 36

so, the speed in these first 5 minutes was 3 km/5 min.

or then in km/h : 36 km/h

between the minutes 25 and 45 the bus drove with a speed of 80km/h.

and the starting point there was at 7 km.

so, the bus drove s-7 km in 20 minutes.

as before, let's first find the scaling factor to deal with a full hour instead of only 20 minutes.

20 × x = 60

x = 3

as before : distance × scaling factor = distance for km/h

(s-7) × 3 = 80

3s - 21 = 80

3s = 101

s = 33.666666666... km

User Felina
by
5.4k points